Return image size in FindImagePos function

[bossydog9]

Suggestion: A return_offset value 9 that returns the width and height of the image.

Whilst not actually an offset, I think an exception could be made and it wouldn't be out of place. Also, since the top-left position (return_offset=0) and the bottom-right position (return_offset=4) can be returned, it's an easy calculation of the return values of return_offset 4 minus the return values of return_offset 0.

[Dorian (MJT support)]

Since the top-left position (return_offset=0) and the bottom-right position (return_offset=4) can be returned, it's an easy calculation of the return values of return_offset 4 minus the return values of return_offset 0.

That's a very good point!

I'll pass this on to Dev

[Marcus Tettmar]

I'm confused. Width and height is always the width and height of the needle image. Which you already know.

[bossydog9]

Yes, but the script doesn't...I know you can get the size, programmatically, using an image object on a dialog, but that's a bit convoluted, don't you think? Given that a significant part of MS concerns images, it's odd that it doesn't have a size function, or does it?

[Marcus Tettmar]

But the needle image is not dynamic. It's created at design time. It's not created at runtime. It's a known quantity. We create all kinds of variables and initialise them at design time. Why not create variables for width and height in the same way. Am I missing something?

[Marcus Tettmar]

BTW - I'm not against the idea of a new function which returns the dimensions - and maybe other properties - of an image file. Something like:

GetImageDimensions>filename,height,width

But doesn't make sense to me to make this part of FindImagePos which uses a known needle anyway.

[bossydog9]

..that'll do nicely...